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Question

log2 2a3b3=61 (where a and b are consecutive natural numbers and a greater than b ) , then the value of a is


A

3

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B

4

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C

5

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D

7

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Solution

The correct option is C

5


log22a3b3 = a3b3If a and b are consecutive natural numbers then a3b3 = 1+3ab

61 = 1 + 3 ×4 × 5

So, a = 5


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