${log}_{2} 16 + {log}_{5} 125$

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Solution

The correct option is B 7
${log}_{2} 16 + {log}_{5} 125 {log}_{2} 2^{4} + {log}_{5} 5^{3} 4 {log}_{2} 2 + 3 {log}_{5} 5 4 + 3 = 7$

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Similar questions

x

{log}_{2} {log}_{0.5} (2^{x} \frac{15}{16}) \leq 2

{log}_{5} 125 + {log}_{6} 216

{log}_{3} 81 + {log}_{5} 125

{log}_{5} 125 + {log}_{7} 49 + {log}_{9} 729

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