${log}_{2} 32 + {log}_{7} 343$

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Solution

${log}_{2} 32 + {log}_{7} 343 {log}_{2} 2^{5} + {log}_{7} 7^{3} 5 {log}_{5} 5 + 3 {log}_{7} 7 5 + 3 = 8$

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Similar questions

{log}_{6} 216 + {log}_{7} 343

${log}_{5} 625 + {log}_{3} 243 + {log}_{7} 343$

{log}_{2} 32 = 5

l o g_{7} 343

l o g_{7} 343

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