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Byju's Answer
Standard XI
Mathematics
Fundamental Laws of Logarithms
log3 2log4 3l...
Question
l
o
g
3
2
l
o
g
4
3
l
o
g
5
4
.
.
.
.
.
.
l
o
g
15
14
l
o
g
16
15.
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Solution
log
3
2
log
4
3
log
5
4
.
.
.
.
.
.
.
.
.
.
log
15
14
log
16
15
=
(
log
3
2
log
4
3
)
log
5
4
×
log
6
5
.
.
.
.
.
.
.
.
.
.
log
15
14
log
16
15
=
log
16
2
=
1
log
2
16
=
1
log
2
2
4
=
1
4
log
2
2
=
1
4
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Similar questions
Q.
Evaluate
log
3
2
log
4
3
log
5
4.....
log
15
14
log
16
15
Q.
The value of
l
o
g
3
2
l
o
g
4
3
l
o
g
5
4
…
l
o
g
15
14
l
o
g
16
15
is
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