The correct option is C 3/2 log_35 × log_2527 = log_35 × 3 log_253 = 3 log_35 ×1/log_325 = 3 log_35 ×1/2log_35 = 3/2 ...

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Logarithmic Inequalities

log 3 5 ×log ...

Question

$l o g_{3} 5 \times l o g_{25} 27 =$

3 log 5

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2/3

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3/2

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-3/2

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Solution

The correct option is C
3/2

$l o g_{3} 5 \times l o g_{25} 27 = l o g_{3} 5 \times 3 l o g_{25} 3$

= $3 l o g_{3} 5 \times \frac{1}{l o g_{3} 25}$

= $3 l o g_{3} 5 \times \frac{1}{2 l o g_{3} 5}$

= $\frac{3}{2}$

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