log 3 + log 9 + log 27 + log 81 is equal to

4log 3

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6log 3

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10log 3

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Can't be determined

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Solution

The correct option is C 10log 3
Given,
log3 + log 9 + log 27 + log 81
$= l o g 3^{1} + l o g 3^{2} + l o g 3^{3} + l o g 3^{4}$
= 1log 3 + 2log 3 + 3log 3 + 4log 3
$[∵ l o g m^{n} = n l o g m]$
=(1 + 2 + 3 + 4)log 3
=10 log 3

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\frac{log 81}{log 27} = x

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