Question

${\log }_{4}28\times {\log }_{\frac{3}{7}}4\times {\log }_3\frac{3}{7}$ is greater than

• A. $3$
• B. $4$
• C. $5$
• D. $6$

Answer 1

Answer: (A)

$3$

$lo{g}_{4}28\times lo{g}_{\frac{3}{7}}4\times lo{g}_3\frac{3}{7}$

$=\frac{log28}{log4}\times \frac{log4}{log\frac{3}{7}}\times \frac{log\frac{3}{7}}{log3}$

$=\frac{log28}{log3}>3$.