${log}_{7} (49) + {log}_{10} (100)$

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Solution

${log}_{7} 49 + {log}_{10} 100 {log}_{7} 7^{2} + {log}_{10} 10^{2} 2 {log}_{7} 7 + 2 {log}_{10} 10 2 + 2 = 4$

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Similar questions

{log}_{5} 125 + {log}_{7} 49 + {log}_{9} 729

In which quadrant following point will lie $({l o g}_{3} 27, - {l o g}_{10} 100)$

{log}_{10} 100 = 2, {log}_{10} 101 = 2.004

{log}_{10} 102 = 2.0086, {log}_{10} 103 = 2.0128

\int_{100}^{103} {log}_{10} x d x

T_{V} = ⎧ ⎪ ⎪ ⎨ ⎪ ⎪ ⎩ \begin{matrix} \frac{π}{4} {(\frac{U}{100})}^{2} & f o r U \leq 60^{\circ /_{\circ}} 1.784 - 0.933 l o g_{10} (100 - U) & U > 60^{\circ /_{\circ}} \end{matrix}

T_{V}

0.003 c m^{2} / s

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