Log(81)+log(243)=a log3 ,then a=

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Solution

Solution-:

log (81)+log(243) = alog3

First we will find the prime factors of 81 and 243

81= 3333= 3^4

243= 3333*3=3^5

So we got log ( 3^4) + log( 3^5)

we know that exponent will come in front
4 log3 + 5 log 3
= 9log 3
When we will compare with a log 3

9log3=alog 3

we got a= 9 answer

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