The correct option is C log _ a x log_bx×log_ab =logxlogb×logbloga =logxloga =log_ax ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Representation of Logarithmic Function

log b x× log ...

Question

${l o g}_{b} x \times {l o g}_{a} b =$

{l o g}_{x} a

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{l o g}_{x} b

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{l o g}_{a} x

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{l o g}_{b} x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C ${l o g}_{a} x$
${log}_{b} x \times {log}_{a} b$
$= \frac{log x}{log b} \times \frac{log b}{log a}$
$= \frac{log x}{log a}$
$= {log}_{a} x$

Suggest Corrections

Similar questions

\frac{{log}_{a} n}{{log}_{a b} n} = 1 + {log}_{a} b

{log}_{a b} x = \frac{{log}_{a} x {log}_{b} x}{{log}_{a} x + {log}_{b} x}

{log}_{x} a

a^{x / 2}

{log}_{b} x

G . P

x

{log}_{x} a, a^{x / 2}, {log}_{b} x

x

{log}_{x} a, a^{x / 2}, {log}_{b} x

G . P

x

If $l o g_{x} a, a^{\frac{x}{2}}$ and $l o g_{b} x$ are in G.P. then write the value of x.

Join BYJU'S Learning Program