Question

$\log \frac{75}{16}-2\log \frac{5}{9}+\log \frac{32}{243}$ is equal to

• A. $\log 2$
• B. $\log 3$
• C. $2\log 2$
• D. None

Answer 1

Answer: (A)

$\log 2$

GE: $\log \frac{75}{16}-2\log \frac{5}{9}+\log \frac{32}{243}$ is equal to $\log \left[\frac{\frac{75}{16}\times \frac{32}{243}}{{\frac{5}{9}}^2}\right]$

$=\log 2$