CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

logKPKC+logRT=0 is a relationship for the reaction:

A
PCl5(g)PCl3(g)+Cl2(g)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2SO2(g)+O2(g)2SO3(g)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
H2(g)+I2(g)2HI(g)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
N2(g)+3H2(g)2NH3(g)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2SO2(g)+O2(g)2SO3(g)
Using Kp=KC(RT)Δng
Taking log on both side
logKp=logKc+ΔnglogRT
logKPKC=ΔnglogRT
So, Δng=1
Δng=Number of mole of gaseous product - Number of mole of gaseous reactant
So for reaction,
2SO2(g)+O2(g)2SO3(g)
Δng=23=1
Hence option (b) is correct.


flag
Suggest Corrections
thumbs-up
58
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon