CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

logKpKc+logRT=0 is a relationship for the reaction

A
PCl5(g)PCl3(g)+Cl2(g)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2SO2(g)+O2(g)2SO3(g)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
H2(g)+I2(g)2HI(g)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
N2(g)+3H2(g)2NH3(g)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2SO2(g)+O2(g)2SO3(g)
We know,
Kp=KC(RT)ng
So, logKp=logKC(RT)ng
logKplogKC=nglog(RT)
logKPKC=nglogRT

So, according to the questionng=1

Hence, for the reaction
2SO2+O22SO3ng=npnR =23 =1

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Third Law of Thermodynamics
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon