Log e 121-A- 2 log e 11B- 11 log e 11C- log e 100-21

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Standard XI

Mathematics

Standard Logarithm

log e 121=A. ...

Question

${log}_{e} 121$ =

2 {log}_{e} 11

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11 {log}_{e} 11

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{log}_{e} 100 + 21

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Solution

The correct option is A $2 {log}_{e} 11$
${log}_{e} 121 = {log}_{e} 11^{2}$
$= 2 {log}_{e} 11$ [As ${log}_{b} a^{n} = n {log}_{b} a$ ]

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loge121 =

The correct option is A 2loge11loge121=loge112 =2loge11 [As logban=nlogba]

${log}_{e} 121$ =

The correct option is A $2 {log}_{e} 11$
${log}_{e} 121 = {log}_{e} 11^{2}$
$= 2 {log}_{e} 11$ [As ${log}_{b} a^{n} = n {log}_{b} a$ ]