Log1-22x - 1 -log1-2x - 1

Consider the given equation. log_1/2(2x+1)=log_1/2(x+1) 2x+1=x+1 2x=x 2x x=0 x=0 . ...

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log1/22x + 1 ...

Question

${log}_{\frac{1}{2}} (2 x + 1) = {log}_{\frac{1}{2}} (x + 1)$

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