$l o g \frac{K_{p}}{K_{c}} + l o g R T = 0$ is true relationship for the following reaction:

{P C l}_{5} ⇌ {P C l}_{3} + {C l}_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 S O_{2} + O_{2} ⇌ 2 S O_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

N_{2} + 3 H_{2} ⇌ 2 N H_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(b)

and

(c)

both

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $2 S O_{2} + O_{2} ⇌ 2 S O_{3}$
$log \frac{K_{p}}{K_{c}} = log R T = 0 \Rightarrow log \frac{K_{p}}{K_{c}} = - log R T$
$\Rightarrow \frac{K_{p}}{K_{c}} = (R T)^{- 1}$ $[\frac{K_{p}}{K_{c}} = (R T)^{Δ H}]$
So here $Δ n$ should be $- 1$
In reaction $2 S O_{2} + O_{2} ⟶ 2 S O_{3}$ $(Δ n = - 1)$

Suggest Corrections

Similar questions

l o g \frac{K_{p}}{K_{c}} + l o g R T = 0

P {C l}_{5} \to P {C l}_{3} + {C l}_{2}

2 {S O}_{2} + O_{2} \to 2 {S O}_{3}

N_{2} + 3 H_{2} \to 2 {N H}_{3}

2 K C l O_{3} \to 2 K C l + 3 O_{2}

log \frac{K_{p}}{K_{c}} + log R T = 0

l o g \frac{K_{p}}{K_{c}} + l o g R T = 0

l o g \frac{K_{p}}{K_{c}} + l o g R T = 0

Join BYJU'S Learning Program