${log}_{x} \frac{1}{4} = - 1$

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Solution

$l o g_{x} \frac{1}{4} = - 1$
$l o g_{x} 4^{- 1} = - 1$
$(- 1) l o g_{x} 4 = (- 1)$
$l o g_{x} 4 = 1$
$4 = x^{1}$
$x = 4$

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