Question

Log2√3^1728=x

Where 2√3 is base and 1728 is a number and x is exponent then find the value of x

Answer 1

Solution:

Let x denote the required logarithm.

Therefore, log_2√3 1728 = x

or, (2√3)^x = 1728 = 2⁶ ∙ 3³ = 2⁶ ∙ (√3)⁶

or, (2√3)^x = (2√3)⁶

Therefore, x = 6.
(Answer)