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Question

Look at the accompanying figure. Line AD || line EH. Line XY and line PQ are their transversals. If m∠CBF = 70° and m∠CGH = 55°. then



(1) m∠EFB = ......
(2) m∠GFY = ......
(3) m∠BCG = .....

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Solution

It is given that line AD ║ line EH and lines XY and PQ are transversals.
Also,
mCBF = 70° and mCGH = 55°

(1) Consider the parallel lines AD and EH and the transversal XY.
CBF and EFB are alternate angles.
Because alternate angles are of the same measure, CBF = EFB.
EFB = 70° (∵ CBF = 70°)

(2) Consider the parallel lines AD and EH and the transversal XY.
CBF and GFY are corresponding angles.
Because corresponding angles are of the same measure, CBF = GFY.
GFY = 70° (∵ CBF = 70°)

(3) Consider the parallel lines AD and EH and the transversal PQ.
CGH and BCG are alternate angles.
Because alternate angles are of the same measure, CGH = BCG.
BCG = 55° (∵ CGH = 55°)

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