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Question

Look at the following table below.

Class intervalClass mark010A1020B203025304035

The value of A & B respectively are:


A

2.5, 7.5

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B

3, 7

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C

2, 7

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D

3,8

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Solution

The correct option is A

2.5, 7.5


Class mark for a class interval = Upperclass limit + Lowerclass limit 2

For 1st class upper class limit is 10 and the lower limit is 0.
Thus class mark = 10+02=5

For 2nd class, the upper-class limit is 20 and the lower limit is 10.
Thus the class mark = 20+102=15


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