wiz-icon
MyQuestionIcon
MyQuestionIcon
13
You visited us 13 times! Enjoying our articles? Unlock Full Access!
Question

Look at the graphs on the left hand side and match them with the corresponding slope-intercept equation form.

A
y = 3x + 2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0.4y = -0.4x + 2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.5y = -1x + 2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

Let's find the slope and y-intercept of the given graphs.

Consider Graph 1:


Slope =Positive risePositive run=31=3

Value of y-intercept = 2

Substitute the values in slope-intercept form, y = mx + c

We get: y=3x+2


Consider Graph 2:


Slope =Negative risePositive run=22=1

Value of y-intercept = 5

Substitute the values in slope intercept form: y = mx + c

We get: y = -x + 5

y=x+5
[Dividing both sides by 2.5, we get]

y2.5=12.5+52.5

0.4y=0.4x+2

So, equation for the second graph can be written as:
0.4y=0.4x+2

Consider Graph 3:


Slope =Negative risePositive run=21=2

Value of y-intercept = 4

Substitute the values in slope intercept form: y = mx + c

We get: y = -2x + 4

y=2x+4
[Dividing both sides by 2, we get]

y2=22+42

0.5y=1x+2

So, equation for the third graph can be written as:
0.5y=1x+2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon