Question

Low spin complex of $d^6$-cation in an octahedral field will have the following energy:
(${\Delta }_0=$ Crystal field splitting energy in an octahedral field, $P=$ Electron pairing energy)

• A. $\frac{-12}{5}{\Delta }_0+3P$
• B. $\frac{-2}{5}{\Delta }_0+2P$
• C. $\frac{-2}{5}{\Delta }_0+P$
• D. $\frac{-12}{5}{\Delta }_0+P$

Answer 1

The correct option is A $\frac{-12}{5}{\Delta }_0+3P$

Low spin complex of $d^6$ cation having ${\Delta }_0>$ P.E

Configuration is $t_2{g}^6{eg}^0$ and 3 electron are paired in $t_{2_g}$ orbital

$=\frac{-2}{5}{\Delta }_0\times 6+3P$

$=\frac{-12}{5}{\Delta }_0+3P$

Hence, the correct option is A.