Question

Low spin complex of $d^6$ cation in an octahedral field will have the following $C.F.S.E$ :

• A. $-\frac{12}{5}{\Delta }_0+P$
• B. $-\frac{12}{5}{\Delta }_0+2P$
• C. $-\frac{2}{5}{\Delta }_0+2P$
• D. $-\frac{2}{5}{\Delta }_0+P$

Answer 1

The correct option is A $-\frac{12}{5}{\Delta }_0+P$

Therefore, total energy=${\Delta }_0+P$

$(+\frac{3}{5}\times 0-\frac{2}{5}\times 6){\Delta }_o+P$

$=-\frac{12}{5}{\Delta }_o+P$.