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Question

Lowering of vapour pressure due to a solute in 1 molal aqueous solution at 100C is

A
13.44 mm Hg
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B
14.12 mm Hg
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C
13.2 mm Hg
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D
35.2 mm Hg
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Solution

The correct option is A 13.44 mm Hg
We know that,
MwB=xB×1000(lXB)MwA
[XB=mole fraction of soluteMWA=mole mass of solvent]
1=xB×1000(lxB)×18
xB=0.0176
xA=10.0176=0.9824
Now,
P=PxA=760×0.9824=746.62
ΔP=PP=760746.62=13.41mmHg(approx)

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