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Question

Lowering of vapour pressure in 2 molal aqueous solution at 373K is____________.

A
0.35 bar
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B
0.022 bar
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C
0.22 bar
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D
0.035 bar
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Solution

The correct option is D 0.035 bar
Given
A solute B have 2 moles in 1 kg of water
Solution
Molality=1
No.of moles of B=Xb
Molality=Xb*1000/(1-Xb)*18
Putting values
Xb=0.0347
No.of moles of Water=Xa
Xa=1-Xb
Xa=0.9653
Pressure of 1 mole =760mmHg
Pressure of 0.9653 mol=760*0.9653=733.628mmHg
Lowering of Vapour pressure=760-733.628=26.372mmHg=0.035 bar
The correct option is D

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