Question

Lowest electronegativity is shown by which of the following element?

$\begin{array}{cccccccc}Period& & & & & & & \\ \downarrow & Group& Group& Group& Group& Group& Group& \\ & 1& 2& 14& 15& 16& 17& \\ 2& \left(A\right)Li& Be& \left(D\right)C& N& O& \left(E\right)F& \\ 3& \left(B\right)Na& Mg....& & & & & \\ 4& \left(C\right)K& & & & & & \end{array}$

• A. $Li$
• B. $Na$
• C. $C$
• D. $K$
• E. $F$

Answer 1

Answer: (D)

$K$

Lowest electronegativity is shown by potassium, $K.$
In a period, electronegativity increases from left to right due to the decrease in size and increase in nuclear charge.
In a group, electronegativity decreases from top to bottom due to increase in atomic size.