Lt cosx/x-pi/2 X->pi/2

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Q. If

tan x = - \frac{4}{3}, \frac{π}{2} < x < π,

then which of the following is/are correct ?

If $- \frac{π}{2} < x < \frac{π}{2}$ and the sum to infinite number of terms of the series $c o s x + \frac{2}{3} c o s x s i n^{2} x + \frac{4}{9} c o s x s i n^{4} x + . . . . .$ is finite, then $x$ lies in the set

\lim_{x \to \frac{π}{2}} (\frac{π}{2} - x) \tan x

L t x \to \frac{π}{4} \frac{\sqrt{2} - cos x - sin x}{(4 x - π)^{2}} =

L t x \to 0 \frac{\sqrt{\frac{1}{2} (1 - cos x)}}{| x |} =

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