Question

$L{t}_{x\to a}\left(f\right(x)+g(x\left)\right)=2andL{t}_{x\to a}\left(f\right(x)-g(x\left)\right)=1thenL{t}_{x\to a}f\left(x\right).g\left(x\right)=$

• A. $\frac{1}{4}$
• B. $\frac{3}{4}$
• C. $\frac{1}{2}$
• D. $1$

Answer 1

The correct option is B $\frac{3}{4}$

$L{t}_{x\to a}f\left(x\right)=\frac{3}{2};L{t}_{x\to a}g\left(x\right)=\frac{1}{2}$
$\therefore L{t}_{x\to a}f\left(x\right)g\left(x\right)=\frac{3}{4}$