Question

Lyophilic colloidal sols are much more stable than lyophobic colloidal sols. This is due to the extensive solvation of lyophilic colloidal sols, which form a protective layer outside it which prevents it from forming associated colloids. Lyophilic colloidal sols also protect lyophobic colloidal sols from precipitation by the action of electrolytes. This is due to the formation of a protective layer by the lyophilic sols outside lyophobic sols. Lyophilic sols are also called protective sols.
Gelatin (lyophilic) protects gold sol (lyophobic) from coagulation on the addition of a solution of sodium chloride. The protective powers of different colloidal sols are measured in terms of gold number.
Gold number is defined as the amount of protective sol in milligrams that prevents the coagulation of 10 mL of a given gold sol on adding 1 mL of a $10\%$ solution of sodium chloride. Thus, the smaller the gold number of a lyophilic sol, the greater is the protective power.

Gold number of hemoglobin is 0.03. Hence 100 mL of gold sol will require what amount of hemoglobin (in g) so that gold is not coagulated by 1 mL of $10\%NaCl$ solution

• A. $3\times {10}^{-1}\text{g}$
• B. $3\times {10}^{-3}\text{g}$
• C. $3\times {10}^{-4}\text{g}$
• D. $3\times {10}^{-2}\text{g}$

Answer 1

The correct option is C $3\times {10}^{-4}\text{g}$

Gold number $=\frac{weightoflyophilicsolinmg}{volumeofgoldsolinmL}\times 10$

Let ${}^{\prime }{x}^{\prime }$ be the weight of lyophilic sol in $mg$. So,
$0.03=\frac{x}{100}\times 10$
$x=0.3mg$
or $3\times {10}^{-4}g$