M-0-1-2 and N-1-2-3- find N-M -N -M

The correct options are A {3,1} C {3,2} For two #160;sets, A and B the set difference of set B from set A is the set of all element in A but not in ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Roster Form

M=0,1,2 and ...

Question

$M = 0, 1, 2$ and $N = 1, 2, 3$ : find (N-M) $\times$ (N $\cap$ M)

{3, 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{3, 2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{3, 3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of the above

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct options are
A ${3, 1}$
C ${3, 2}$
For two sets, A and B the set difference of set B from set A is the set of all element in A but not in B.
Example:
$A = {a, b, c, d}$
$B = {c, d, e}$
$A - B = {a, b}$
$M = {0, 1, 2}$
$N = {1, 2, 3}$
$N - M = {3}$
$N \cap M = {1, 2}$
$(N - M) \times (N \cap M)$ $= {3, 1}, {3, 2}$

Suggest Corrections

Similar questions

Q. Given

M = (0, 1, 2)

and

N = (1, 2, 3)

. Find

(N - M) \times (N \cap M)

Q. Given

M = (0, 1, 2)

and

N = (1, 2, 3)

. Find

(M \cup N) \times (M - N)

Q. Given M={0,1,2} and N={1,2,3}, then (M

\cup

\times

(M-N) contains

The roster form of the set ${x : x = \frac{n}{2 n + 1}, where n ϵ N and n < 4}$ is ________.

Q. If

S_{1}, S_{2}, S_{3}

, ..........

S_{m}

are the sums of n terms of m A.P.'s whose first terms are 1,2,3,........ ..... m and common differences are 1,3,5,.......... .2m - 1 respectively, then

S_{1} + S_{2} + S_{3} + . . . . . . . . S_{m} =

Join BYJU'S Learning Program

M=0,1,2 and N=1,2,3: find (N-M) ×(N ∩M)

The correct options are A {3,1} C {3,2}For two sets, A and B the set difference of set B from set A is the set of all element in A but not in B.Example:A={a,b,c,d}B={c,d,e}A−B={a,b}M={0,1,2}N={1,2,3}N−M={3}N∩M={1,2}(N−M)×(N∩M) ={3,1},{3,2}

$M = 0, 1, 2$ and $N = 1, 2, 3$ : find (N-M) $\times$ (N $\cap$ M)