$M^{- 2}$ configure is $1 s^{2} 2 s^{2} 2 p^{6}$ , then $M^{+ 2}$ configuration will be :

1 s^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 s^{2} 2 s^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 s^{2} 2 s^{2} 2 p^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1 s^{2} 2 s^{2} 2 p^{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $1 s^{2} 2 s^{2} 2 p^{2}$
In $M^{- 2}$ number of electron are 10. In $M^{+ 2}$ number of electron will be 6.
Only option C has 6 electrons.

Suggest Corrections

Similar questions

Element	Subshell electronic configuration	No. of the outer most shell	Period number
$_{4} B e$	$1 s^{2} 2 s^{2}$	$2$	$2$
$_{6} C$	$1 s^{2} 2 s^{2} 2 p^{2}$	$2$	$2$
$_{11} N a$	$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}$	$3$	-
$_{19} K$	$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{1}$		-

B

1 s^{2} 2 s^{2}

1 s^{2}

2 s^{2}

2 p^{6}

3 s^{2}

3 p^{6}

3 d^{5}

4 s^{2}

1 s^{2}

1 s^{2} 2 s^{2} 2 p^{2}

1 s^{2} 2 s^{2} 2 p^{5}

1 s^{2} 2 s^{2} 2 p^{4}

Element	Subshell electronic configuration	No. of electrons present in the last subshell	Group number
$L i$	$1 s^{2} 2 s^{2}$	$1$	$1$
$N a$	$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1}$	-	$1$
$M g$	$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2}$	-	$2$
$C a$	$1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 s^{2} 3 p^{6} 4 s^{2}$	-	-

Join BYJU'S Learning Program