Question

$M^{3+}$ ion has its electronic configuration as $\left[Ar\right]3d^{10}4s^2$. The element lies in:

• A. $s$-block
• B. $p$-block
• C. $d$-block
• D. $f$-block

Answer 1

The correct option is B $p$-block

The element 'M' has three more electrons than $M^{3+}$. Electronic configuration of M will be $\left[Ar\right]3d^{10}4s^{2}4p^3$.
Since the last electron enters into the $p$ subshell, the element belongs to the $p$-block in the periodic table.