$M^{+ 3}$ ion loses $3 e^{-}$ . Its oxidation number will be

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-3

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Solution

The correct option is C
+6

Looking at the ion $M^{3 +}$ - clearly the oxidation number is +3.

Further - $M^{3 +}$ loses 3 electrons to be come $M^{6 +}$ .
Hence - the new oxidation number is 6.

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Similar questions

$M^{+ 3}$ ion loses $3 e^{-}$ . Its oxidation number will be

M^{3 +}

M n^{+ 3}

M^{+ 3}

2 e^{-}

M^{3 +}

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