Question

$m-\frac{5}{m}=4m+5$

Answer 1

An equation is quadratic in variable x if it is of the form ax² +bx+c=0, where a ,b and c are real numbers and a $\ne$0 .
Given: m –$\frac{5}{m}$ = 4m + 5
On multiplying both sides by m, we get:
m² – 5 = 4m² + 5m
On transposing all the terms from the right-hand side to the left-hand side, we get:
m² – 5 – 4m² – 5m = 0
=> – 3m² – 5m – 5 = 0
On comparing this equation with the general form of the quadratic equation, we find that the given equation is a quadratic in variable m, where a = –3, b = –5 and c = –5.
These are real numbers and a $\ne$ 0.