Question

$M\left(CO{)}_x\right(NO{)}_y\underset{-CO}{\stackrel{+NO}{\to }}M(NO{)}_z$
Where $EAN$ of metal $\left(M\right)$ in both product and reactant is same and it is $54$. Then calculate value of $(x+y-z)$. (where $x,y$ and $z$ are natural numbers and $M$ belong to $6^{th}$ group according to long form of periodic table).

• A. 1
• B. 4
• C. 6
• D. None of these

Answer 1

Answer: (D)

None of these

$\text{Effective atomic number (EAN),}$a number that represents the total number of electrons surrounding the nucleus of a metal atom in a metal complex. It is composed of the metal atom's electrons and the bonding electrons from the surrounding electron-donating atoms and molecules.

and calculated as

$EAN=\text{Atomic number of central atom - oxidation number + Total number of electron gain}$

here,

$Mo\left(CO{)}_x\right(NO{)}_y\underset{-CO}{\stackrel{+NO}{\to }}Mo(NO{)}_z$

according to question

$\text{EAN of M in reactant = EAN of M in product}=54$

i.e

$M-0+(1\times x+1\times y)=M-0+1\times z=54$

$M+x+y=M+z=54$

$M+x+y=M+z$

$\Rightarrow x+y-z=0$

thus, the correct answer is D.