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Byju's Answer
Standard X
Chemistry
Volume of Gases and Number of Moles
Question 6 m ...
Question
Question 6
m
−
m
−
1
2
=
1
−
m
−
2
3
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Solution
m
−
m
−
1
2
=
1
−
m
−
2
3
⇒
2
m
−
m
+
1
2
=
3
−
m
+
2
3
⇒
m
+
1
2
=
5
−
m
3
⇒
3
(
m
+
1
)
=
2
(
5
−
m
)
⇒
3
m
+
3
=
10
−
2
m
⇒
3
m
+
2
m
=
10
−
3
⇒
5
m
=
7
⇒
m
=
7
5
⇒
Check:
⇒
7
5
−
7
5
−
1
2
= 1-
7
5
−
2
3
⇒
7
5
−
7
−
5
5
2
=
1
−
7
−
10
5
3
⇒
7
5
−
2
5
×
2
=
1
−
−
3
5
×
3
⇒
7
5
−
1
5
=
1
+
1
5
⇒
7
−
1
5
=
5
+
1
5
⇒
6
5
=
6
5
⇒
L
.
H
.
S
.
=
R
.
H
.
S
Therefore, it is correct
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7
Similar questions
Q.
Question 6
m
−
m
−
1
2
=
1
−
m
−
2
3
Q.
Question 75
Solve the following:
m
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Q.
Question 75
Solve the following:
m
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Q.
If
∣
∣ ∣ ∣
∣
1
1
1
m
C
1
m
+
3
C
1
m
+
6
C
1
m
C
2
m
+
3
C
2
m
+
6
C
2
∣
∣ ∣ ∣
∣
=
2
α
3
β
5
γ
then
α
+
β
+
γ
is equal to
Q.
If
∣
∣ ∣ ∣
∣
1
1
1
m
C
1
m
+
3
C
1
m
+
6
C
1
m
C
2
m
+
3
C
2
m
+
6
C
2
∣
∣ ∣ ∣
∣
=
2
α
3
β
5
γ
, then
α
+
β
+
γ
is equal
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Volume of Gases and Number of Moles
Standard X Chemistry
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