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Question

M.I. of a uniform circular disk about diameter is I. it's M.I. about an axis perpendicular to its plane and passing through a point on its rim will be.

A
2I
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B
3I
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C
5I
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D
6I
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Solution

The correct option is D 6I
Given-* Moment of Inertia about one of its diameter is (I) we Rnow that Moment of Inertia of a disc of mass (M) and Radius(R) about an axis passing through its centre and perpendicular to the plane. is - I1=MR22
By perpendicular axis theorem, moment of inertia of a disc about its diameter paratel to the plane is- I11+I11=IL=MR22I11=MR24=I (given)
Now by parallel axis theorem, moment of inertia about an axis tangent to the disc and parallel to the plane will be- I=MR22+MR2=32MR2=6I

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