M is a point on side BC of a triangle ABC such that AM is the bisector of ∠BAC. Is it true to say that perimeter of the triangle is greater than 2 AM? If True enter 1, else if False enter 0.
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Solution
Given, △ABC, AM is bisector of ∠BAC Now, In △ABM, AB+BM>AM (Sum of two sides of triangle is greater than the third side) Now, In △ACM, AC+CM>AM (Sum of two sides of triangle is greater than the third side) Thus, adding both, AB+BM+AC+CM>2AM AB+AC+BC>2AM