$M$ kilograms of a material are to be kept in melted state at melting point and power required for this purpose is $P$ . When power source is disconnected then the sample completely solidifies in $t$ sec. The latent heat of fusion of the material will be :

\frac{M}{P t}

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\frac{P t}{M}

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P t M

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P t

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Solution

The correct option is B $\frac{P t}{M}$
We know,

$Q = M L_{f}$ $L_{f}$ = latent heat of fusion.

And Power= $\frac{Q}{t}$

$P t = M L_{f}$

$L_{f} = \frac{P t}{M}$

Option $B$ is the correct answer.

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M kilograms of a material are to be kept in melted state at melting point and power required for this purpose is P. When power source is disconnected then the sample completely solidifies in t sec. The latent heat of fusion of the material will be :

The correct option is B PtMWe know,Q=MLf Lf= latent heat of fusion.And Power= QtPt=MLfLf=PtMOption B is the correct answer.

$M$ kilograms of a material are to be kept in melted state at melting point and power required for this purpose is $P$ . When power source is disconnected then the sample completely solidifies in $t$ sec. The latent heat of fusion of the material will be :

The correct option is B $\frac{P t}{M}$
We know,

$Q = M L_{f}$ $L_{f}$ = latent heat of fusion.

And Power= $\frac{Q}{t}$

$P t = M L_{f}$

$L_{f} = \frac{P t}{M}$

Option $B$ is the correct answer.