Now, if 'P' stands for 6, 'M' for 4 and 'Q' for 5, then what is the difference between the sums of M and S and the sum of P and A ?
A
10
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B
15
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C
25
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D
5
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Solution
The correct option is D 5 Given, P = 6 , M = 4 and Q = 5. 4 N 6 x 6 N S 5 N N 5 5 6 x N 6 4 A N Where A = 5 + 6 = 11 so A = 1 & carry over 1 + S + 5 = 14, So S = 8 Therefore, 4 N 6 x 6 N 8 5 N +N 5 5 6 x N 6 4 1 N From the first row of multiplication it is clear that N ×× 6 = N
So, N can be either 2 or 4 or 6 or 8 or 0.
also, taking into consideration the second multiplication of N ×× N + carryover = 5 (in units place) , only N=2 fits