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Question

M N P
x P N
--------------------
S Q N
N Q Q P x
--------------------------
N P M A N
Now, if 'P' stands for 6, 'M' for 4 and 'Q' for 5, then what is the difference between the sums of M and S and the sum of P and A ?

A
10
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B
15
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C
25
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D
5
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Solution

The correct option is D 5
Given, P = 6 , M = 4 and Q = 5.
4 N 6
x 6 N
S 5 N
N 5 5 6 x
N 6 4 A N
Where A = 5 + 6 = 11 so A = 1 & carry over 1 + S + 5 = 14, So S = 8
Therefore,
4 N 6
x 6 N
8 5 N
+N 5 5 6 x
N 6 4 1 N
From the first row of multiplication it is clear that N ×× 6 = N
So, N can be either 2 or 4 or 6 or 8 or 0.
also, taking into consideration the second multiplication of N ×× N + carryover = 5 (in units place) , only N=2 fits
So, N = 2.
Also, N ×× 4 = 2 ×× 4 = 8
So, S = 8.
(M+S) - (P+A) = (4+8) - (6+1) = 12 - 7 = 5. (option D )

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