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Question

M(OH)x has Ksp=4×1012 and solubility =104 M . Then the value of x is:

A
1
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B
2
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C
3
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D
4
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Solution

The correct option is B 2
M(OH)x will ionise as
M(OH)xM+x+x OH
104 x×104

Ksp=[M+x][OH]x


putting the values,
(104)(x×104)x=4×1012
By inspection, we can find that the relation will hold good,
when x=2.

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