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Byju's Answer
Standard XII
Chemistry
Solubility Product
M OH x has K ...
Question
M
(
O
H
)
x
has
K
s
p
=
4
×
10
−
12
and solubility
=
10
−
4
M
. Then the value of
x
is:
A
1
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B
2
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C
3
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D
4
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Solution
The correct option is
B
2
M
(
O
H
)
x
will ionise as
M
(
O
H
)
x
⇌
M
+
x
+
x
O
H
−
10
−
4
x
×
10
−
4
∴
K
s
p
=
[
M
+
x
]
[
O
H
−
]
x
putting the values,
∴
(
10
−
4
)
(
x
×
10
−
4
)
x
=
4
×
10
−
12
By inspection, we can find that the relation will hold good,
when
x
=
2
.
Suggest Corrections
0
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