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Question

Mp denotes the mass of a proton and Mn that of a neutron. A given nucleus, of binding energy B, contains Z protons and N neutrons. The mass M(N,Z) of the nucleus is given by: (c is the velocity of light)

A
M(N,Z)=NMn+ZMp+Bc2
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B
M(N,Z)=NMn+ZMpBc2
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C
M(N,Z)=NMn+ZMp+Bc2
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D
M(N,Z)=NMn+ZMpBc2
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Solution

The correct option is B M(N,Z)=NMn+ZMpBc2
Sol: BE=Δmc2 formula
Be=[NMn+ZMpM(A,Z)]C2
BEC2=(AZ)Mn+ZMpM(A,Z)
N=AZ
M(A,Z)=ZMp+(AZ)MnBEC2
M(A,Z)=ZMp+NMnbC2
N=AZ
Here, Mp:Mass of proton
Mn:Mass of electron

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