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Question

Mp denotes the mass of a proton and Mn that of a neutron. A given nucleus, of binding energy B, contains Z protons and N neutrons. The mass M(N,Z) of the nucleus is given by
(c is the velocity of light)

A
M(N,Z)=NMn+ZMp+B/c2
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B
M(N,Z)=NMn+ZMpBc2
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C
M(N,Z)=NMn+ZMp+B/c2
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D
M(N,Z)=NMn+ZMpB/c2
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Solution

The correct option is D M(N,Z)=NMn+ZMpB/c2
Mass defect Δm=Bc2

Also,

Mass defect = Total Mass of protons + Total Mass of neutrons - Mass of the nucleus

Mass of the nucleus = Total Mass of protons + Total Mass of neutrons - Mass defect.

M(N,Z)=NMn+ZMpBc2

Hence, the option (D) is correct.

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