Question

$M\text{kg}$ of water at ${20}^{\circ }\text{C}$ is brought to its boiling point. If the heat energy gained by $M\text{kg}$ of water is $3360\text{kJ}$, find the value of $M$.
(Specific heat of water $=4.2{\text{kJ/kg}}^{\circ }\text{C}$)

• A. $5$
• B. $8$
• C. $10$
• D. $12$

Answer 1

The correct option is C $10$

Boiling temperature of water $={100}^{o}C$
We know,
Heat energy, $Q=Mc\Delta T$

$\therefore Q=M\times 4.2\times (100-20)$
$\Rightarrow 3360=4.2\times 80\times M$
$\Rightarrow M=10\text{kg}$