Question

$\frac{m^3}{64}+\frac{n^3}{27}$

Answer 1

$$\begin{gathered} \frac{m^3}{64}+\frac{n^3}{27} \\ ={\left(\frac{m}{4}\right)}^3+{\left(\frac{n}{3}\right)}^3 \\ =\left(\frac{m}{4}+\frac{n}{3}\right)\left[{\left(\frac{m}{4}\right)}^2-\frac{m}{4}\times \frac{n}{3}+{\left(\frac{n}{3}\right)}^2\right] \\ =\left(\frac{m}{4}+\frac{n}{3}\right)\left[\frac{m^2}{16}-\frac{mn}{12}+\frac{n^2}{9}\right] \end{gathered}$$