CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

(ma+nb):b::(mc+nd):d, prove a,b,c,d are in proportion by using componendo and dividendo


Solution

ma+nb   = mc+nd
    b               d    

 d(ma+nb)=b(mc+nd)

dma+dnb=bmc+bnd

dma-bmc=bnd-dnb

m(da-bc)=n(bd-db)

m(da-bc)=n(0)

m(da-bc)=0

da-bc=0
           m     

da-bc=0

da=bc

      = c
     b     d

=> thus, a,b,c and d are in proportion.
       hence proved
 

Mathematics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image