Question

Mac ran 2$\frac{7}{8}$ mi on Monday and 5$\frac{1}{2}$ mi on Tuesday. How much distance did he cover in two days?

• A. $\frac{53}{8}$ mi
• B. $\frac{57}{8}$ mi
• C. $\frac{53}{8}$ mi
• D. $\frac{67}{8}$ mi

Answer 1

The correct option is D $\frac{67}{8}$ mi

Distance covered on Monday
$=2\frac{7}{8}$ mi

Distance covered on Tuesday
$=5\frac{1}{2}$ mi

$\therefore$ Distance covered in two days
$=(2\frac{7}{8}+5\frac{1}{2})$ mi

$2\frac{7}{8}=\frac{2\times 8+7}{8}=\frac{23}{8}$

$5\frac{1}{2}=\frac{5\times 2+1}{2}=\frac{11}{2}$

$\therefore 2\frac{7}{8}+5\frac{1}{2}=\frac{23}{8}$ + $\frac{11}{2}$

LCM of 2 and 8 = 8

$\therefore \frac{11}{2}=\frac{11\times 4}{2\times 4}=\frac{44}{8}$

$\therefore 2\frac{7}{8}+5\frac{1}{2}=\frac{23}{8}+\frac{44}{8}=\frac{23+44}{8}=\frac{67}{8}$

$\therefore$ Mac covered $\frac{67}{8}$ mi in two days.