Madhu has divided the rectangle given into $2$ triangles. The red triangle is half of the big rectangle. Area of the big rectangle is $20$ square cm. So the area of the red triangle is _________ square cm.

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Solution

the area of the red triangle is 10 square cm.
Since the red triangle is half of the big rectangle therefore area of red triangle = 10 sq cm

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Madhu has divided the rectangle given into 2 triangles. The red triangle is half of the big rectangle. Area of the big rectangle is 20 square cm. So the area of the red triangle is _________ square cm.

the area of the red triangle is 10 square cm.Since the red triangle is half of the big rectangle therefore area of red triangle = 10 sq cm

Madhu has divided the rectangle given into $2$ triangles. The red triangle is half of the big rectangle. Area of the big rectangle is $20$ square cm. So the area of the red triangle is _________ square cm.

the area of the red triangle is 10 square cm.
Since the red triangle is half of the big rectangle therefore area of red triangle = 10 sq cm