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Question

Magnesium hydroxide, Mg(OH)2 is the white milky substance in milk of magnesia. What mass of Mg(OH)2 is formed when 15 mL of 0.18 M NaOH are combined with 12 mi. of 0.14 M MgCl2 ? The molar mass of Mg(OH)2 is 58.3 g mol1.

A
0.079 g
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B
0.097 g
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C
0.16 g
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D
0.31 g
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Solution

The correct option is A 0.079 g
MgCl2+2NaOHMg(OH)2+2NaCl

moles of NaOH in 15 ml of 0.18 M solution = 0.18151000 = 0.0027
moles ofMgCl2 in 12 ml of 0.14 M solution = 0.00168
according to above equation, for 1 mole of MgCl2 we require 1 mole of NaOH
so, NaOH is a limiting reagent
so, moles of Mg(OH)2 produced = 0.00272 = 0.0013
so, mass of Mg(OH)2 produced = moles * molar mass = 0.0013 * 58.3 = 0.079 g

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